Will mark !

the number of chips of different colors in amy's bag is shown below:

8 blue chips

9 pink chips

1 white chip

amy takes out a chip from the bag randomly without looking. she replaces the chip and then takes out another chip from the bag. what is the probability that amy takes out a pink chip in both draws?

9 over 18 multiplied by 8 over 17 equals 72 over 306

9 over 18 plus 8 over 17 equals 297 over 306

9 over 18 multiplied by 9 over 18 equals 81 over 324

9 over 18 plus 9 over 18 equals 18 over 18

(9/18)(9/18) = 81/324. The probability that Amy takes out pink chips in both draws is 81/324.

In this example we will use the probability property P(A∩B), which means given two independent events A and B, their joint probability P(A∩B) can be expressed as the product of the individual probabilities P(A∩B) = P(A)P(B).

The total number of chips of different colors in Amy's bag is:

8 blue chips + 9 pink chips + 1 white chip = 18 color chips

Amy takes out a chip from the bag randomly without looking, she replaces the chip and then takes out another chip from the bag.

So, the probability that Amy takes out a pink chip in the first draw is:

P(A) = 9/18 The probability of takes out a pink chip is 9/18 because there are 9 pink chips in the total of 18 color chips.

Then, Amy replaces the chip an takes out another which means there are again 18 color chips divide into 8 blue chips, 9 pink chips, and 1 white chip. So, the probability of takes out a pink chip in the second draw is:

P(B) = 9/18  The probability of takes out a pink chip is 9/18 because there are 9 pink chips in the total of 18 color chips.

What is the probability that Amy takes out a pink chip in both draws?

P(A∩B) = P(A)P(B)

P(A∩B) = (9/18)(9/18) = 81/324

7. d. 64

8. i. 32

9. c. 125

10. j. none of the above

11. d. 81

12. i. 216

13. e. none of the above

14. g. 240

15. e. none of the above

16. g. 32

17.   e. none of the above