Aceiling light has a cross-section in the shape of a parabola. the parabola is 24 cm wide and 9 cm deep. the lightbulb is located at the focus of the parabola. how far from the vertex is the lightbulb?

  4 cm

Step-by-step explanation:

The equation of a parabola with its vertex at the origin can be written as ...

  y = 1/(4p)x^2

The problem statement tells us that one point on the parabola is (x, y) = (12, 9). We can put these values into the equation and solve for p, the distance from the focus to the vertex.

  9 = 1/(4p)(12^2)

  9×4/144 = 1/p = 1/4 . . . . . . . . multiply by the inverse of the coefficient of 1/p

Then p = 4, and the bulb is 4 cm from the vertex.

395.84

step-by-step explanation:

2πrh+2πr²

2 (pie)(radius)(height)+2(pie)(radius)^2

true? is that what you're asking or do you mean something else?