In 1990 the enrollment at trenton east high school was 840. from 1990 through 1996 the enrollment increased at an average rate of 24 students per year. write a linear model for the enrollment at trenton east high school. let x represent the number of years since 1990. trenton east was built to hold 900 students. write a linear inequality that represents the possible number of years since 1990 when the school's enrollment was less than the maximum capacity for which the school was built. solve the inequality.

See below in bold.

Step-by-step explanation:

Linear model:

E = 24x + 840   where E is the  enrolment .

If there are 900 students then

900 = 24x + 840

24x = 900-840 = 60

For  E < 900 we have the inequality

24x < 60

x < 2.5

As we are dealing in years our answer is

x <  3 years .

i think it would be 43 movies that would have to be watched.

step-by-step explanation:

think about it. for the second plan, every month is 8 dollars. 8 x 12= 96. so thats the number for the second plan. now for the first plan, its annual meaning you have to pay 10 dollars every year. so now you have to get an equivalent amount of 86 since 96-10=86. 86 divided by 2 since every movie costs 2$ then you would have to watch 43 movies a year to get the same as the second plan. i really hoped this . have a wonderful day as well!