The function f(t)= -5t^2+20t +60 models the approximate height of an object t seconds after it is launched. how many seconds does it take the objects to hit the ground?

t = 6: It takes 6 seconds for the object to hit the ground

Step-by-step explanation:

So, we need to find t when the height is 0. Since -5t² + 20t + 60 represents the height, that needs to equal 0.

Equation: -5t² + 20t + 60 = 0

Divide by -5: t² - 4t - 12 = 0

Find two numbers that add up to -4t and multiply to -12t²: -6t, 2t

Substitute: t² - 6t + 2t - 12 = 0

Factor: (t - 6)(t + 2) = 0

Answers: t = 6, t = -2

Since time can't be negative, t = 6.

c.

step-by-step explanation:

substitution for (0,1)

y=x^2+4x+1

1=0^2+4(x)0+1

1=0+4(x)0+1

1=4(x)0+1

1=0+1

1=1

substitution for (-3,-2)

y=x+1

-2=-3+1

-2=-2

answer: 7. if the functions had a negative leading coefficient and is of even degree, which statement about the graph is true?

step-by-step explanation: