Find the value of this function 2x+3-x²-1*4

x_1= √-28/-2

x_2= 2 + √-28

Quadratic formula method: ↓

Step-by-step explanation:

Given) 2x + 3 - x² - 1 * 4

1) Communtative Property: 2x + 3 - x² - 1 * 4 = -x² - 1 * 4 + 2x + 3

2) Communtative Property: -x² - 1 * 4 + 2x + 3 = -x² + 2x - 1 * 4 + 3

3) Communtative Property: 2x - x² - 1 * 4 + 3

4) Solve: 2x - x² - 1 * 4 + 3

5) Solve: 2x - x² - 4 + 3

6) 2x - x² - 7

7) Communtative Property: -x² + 2x - 7

8a) Quadratic Formula: ax²+bx+c=0; x = ((-b)± √(b²-4ac))/2a

8b) Let -1=a, let 2=b, let -7=c

9a) Substitute -1 for a: x = ((-b)± √(b²-4(-1)c))/2(-1)

9b) Substitute 2 for b: x = ((-2)± √(2²-4(-1)c))/2(-1)

9c) Substitute -7 for c: x = ((-2)± √(2²-4(-1)(-7))/2(-1)

10a) Solve: (-2± √2²-4(-1)(-7))/-2 = (-2± √4 -4(-1)(-7))/-2

10b) Solve: (-2± √4 -4(-1)(-7))/2(-1) = (-2± √4+ -4(-1)(-7))/-2

11) Solve: (-2± √4 + -4(-1)(-7))/-2 = (-2± √4 + (4)(-7))/-2 = (-2± √4 + -28)/-2

12) Solve: (-2± √4 + √-28)/-2 = (-2±  2 + √-28)/-2

13a) Solve 1 way: (-2+  2 + √-28)/-2 = (0 + √-28)/-2 =

x_1= √-28/-2

13b) Solve 2 way: (-2-  2 + √-28)/-2 = (-4 + √-28)/-2 =

x_2= 2 + √-28

14) Or solve a different way... I'm pretty sure theres another, more accurate way to solve this. :(

I hope I helped. I wasn't very sure on how to do this though, sorry if I am wrong. :(

answer: 298143

step-by-step explanation:

step-by-step explanation:

sry but any answer choices