The table below shows two equations: equation 1 |4x − 3|− 5 = 4 equation 2 |2x + 3| + 8 = 3 which statement is true about the solution to the two equations? * equation 1 and equation 2 have no solutions. * equation 1 has no solution, and equation 2 has solutions x = −4, 1. * the solutions to equation 1 are x = 3, −1.5, and equation 2 has no solution. * * the solutions to equation 1 are x = 3, −1.5, and equation 2 has solutions x = −4, 1.

Option C is correct.

Step-by-step explanation:

Equation 1|4x − 3|− 5 = 4

Adding +5 on both sides

|4x − 3|− 5 +5 = 4 +5

|4x − 3| = 9

Apply absolute rule:

IuI = a and a>0 then u = a and u = -a

so, 4x-3 = 9 and 4x-3 = -9

Solving

4x = 9+3   and 4x = -9+3

4x = 12      and 4x = -6

x = 12/4     and x = -6/4

x = 3          and x = -3/2 or -1.5

Equation 2|2x + 3| + 8 = 3

Adding -8 on both sides

|2x + 3| + 8 -8 = 3 -8

|2x + 3|  = -5

Apply absolute rule:

IuI = a and a>0 then u = a and u = -a

But we cannot apply absolute rule because in our case a < 0 i.e -5

So, Equation 2 has no solutions.

Hence Option C The solutions to equation 1 are x = 3, −1.5, and equation 2 has no solution is correct.

c

step-by-step explanation:

i think because what else can be a sample of every member

part a

answer: a reasonable domain is where n is a real number. so n can be between 0 and 10. both endpoints are included.

work shown:

n is the number of days after the experiment starts. the smallest n can be is n = 0 which means that 0 days have gone by, and we're at the start. to find out how large n should be, then replace f(n) with 16.13 and solve for n. use logarithms to isolate the exponent.

f(n) = 12*(1.03)^n

16.13 = 12*(1.03)^n

16.13/12 = (1.03)^n

1.34416666666667 = (1.03)^n

(1.03)^n = 1.34416666666667

log[ (1.03)^n ] = log[ 1.34416666666667 ]

n*log[ 1.03 ] = log[ 1.34416666666667 ]

n = log[ 1.34416666666667 ]/log[ 1.03 ]

n = 10.0062999823929

this rounds to n = 10 which is fairly close but not 100% perfect. so this is the largest n can be.

note: if you plug n = 10 into f(n), you'll get roughly 16.127 which rounds to 16.13 (this comes up again in part c)

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part b

answer: the y intercept is 12. it represents the starting height of the plant in cm.

work shown:

plug n = 0 into the f(n) function. simplify

f(n) = 12*(1.03)^n

f(0) = 12*(1.03)^0

f(0) = 12*(1)

f(0) = 12

on day n = 0, aka the starting point, the height f(n) is 12 cm

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part c

answer: the average rate of change is approximately 0.43061036458991 (round however you need to). this represents the average growth rate from day n = 3 to day n = 10. so the plant grew roughly 0.43 cm per day during this timespan, assuming you round to 2 decimal places.

work shown:

compute f(3)

f(n) = 12*(1.03)^n

f(3) = 12*(1.03)^3

f(3) = 13.112724 < we'll use this later

compute f(10)

f(n) = 12*(1.03)^n

f(10) = 12*(1.03)^10

f(10) = 16.1269965521294 < we'll use this later

now use the formula below with a = 3 and b = 10

aroc = average rate of change

aroc = [ f(b) - f(a) ]/[ b - a ]

aroc = [ f(10) - f(3) ]/[ 10 - 3 ]

aroc = (16.1269965521294 - 13.112724)/(10 - 3)

aroc = 3.0142725521294/7

aroc = 0.43061036458991

round this however you need to

note: the plant grew approximately 3.01 cm over 7 days, so roughly 0.43 cm per day is the average growth rate (if you were to round to 2 decimal places).