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Mathematics, 29.06.2019 22:10 sammilower04
Atruncated cube is a convex polyhedron with 36 edges and 24 vertices. a truncated tetrahedron is a convex polyhedron with 18 edges and 12 vertices. how do the number of faces of a truncated cube and a truncated tetrahedron compare? a)the truncated cube has 6 more faces than the truncated tetrahedron. b)the truncated cube has 8 more faces than the truncated tetrahedron. c)the truncated cube has 12 more faces than the truncated tetrahedron. d)the truncated cube has 18 more faces than the truncated tetrahedron.
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Atruncated cube is a convex polyhedron with 36 edges and 24 vertices. a truncated tetrahedron is a c...
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