Are f(x) and g(x) inverse functions across the domain [5, + ? ) f(x) = _/{x-5} +4 g(x) = (x-4)2 +5 a. no , because _/g(x)-5 + 4 = x b. yes because _/ g(x) -5 +4 = x c. yes because _/ x-5 +4/(x-4)2 +5 d. no, because [_/ x-5 +4] / [(x-4)2 +5] = x

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

answer: 75°

step-by-step explanation:

∠esk is the supplement of ∠edk, so is 100°. ∠esd = 1/2·arc ed, so is 25°.

since ∠esk = ∠esd + ∠dsk

you have 100° = 25° + ∠dsk . .

fill in known values 75° = ∠dsk . . . . .

subtract 25°

step-by-step explanation:

the answer would be c