An art student wishes to create a clay sphere as part of a sculpture. if the clay’s density is approximately 88 pounds per cubic foot and the sphere’s radius is 2 feet, what is the weight of the sphere to the nearest pound? use 3.14 for pi, and enter the number only.

The weight of the sphere = 2947 pounds

Step-by-step explanation:

* Lets revise the volume of the sphere

- The volume of the sphere is 4/3 π r³, where r is the radius of

  the sphere

- Density = mass ÷ volume

- Mass is the weight and volume is the size, so density is weight

 divided through size

- Density = weight ÷ volume

* Now lets solve the problem

∵ The clay's density ≅ 88 pounds/cubic foot

∵ The radius of the sphere is 2 feet

∵ The volume of the sphere = 4/3 π r³

∴ The volume of the sphere = 4/3 π (2)³ = 32/3 π feet³

∵ Density = weight/volume ⇒ by using cross multiply

∴ Weight = density × volume

∵ Density = 88 pounds/foot³

∵ Volume = 32/3 π feet³

∵ π = 3.14

∴ The weight of the sphere = 88 × 32/3 × 3.14 = 2947 pounds

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

entering that problem on the tube might get you an answer