Positive skewness of a distribution could be caused by which of the following choices: a. an extremely low value b. an extremely high value c. a value close to the mean d. a value close to the median

In positively skewed distributions, the mean is usually greater than the median, which is always greater than the mode

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.

idk

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