Abox contains shirts in two different colors and two different sizes. the numbers of shirts of each color and size are given in the table.

shirt color size
large medium total
red 42 48 90
blue 35 40 75
total 77 88 165

from the data given in the table, we can infer that

v possible answers v
a. p(red shirt | large shirt) = p(large shirt)
b. p(blue shirt | large shirt) = p(blue shirt)
c. p(shirt is medium and blue) = p(medium shirt)
d. p(large shirt | red shirt) = p(red shirt)

how long did the flood last

step-by-step explanation:

then i will answer

step-by-step explanation:

once you graph it hit 2nd (the blue button) and graph

that takes you to a table of coordinates

on the left is x coordinates and on the right is y coordinates and an empty box

(you may have to scroll up/down in order to get ( x, 0)

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.