Identify the vertex and the y-intercept of the graph of the function y=-2(x+3)^2 +2.

we can simplify it to this:

so we know it , the intercept in a standard equation of a parabola is C:

so the intercept is (-16) and for the vertex use:

x=-b/2a

so now put it in the equation and get the y of vertex:

y=-18+36-16=2 ==>vertex(-3,2)

the f

last graph i believe

step-by-step explanation:

worked it out i believe

50- 250 is correct i did that one too

step-by-step explanation: