Find x and h in this trinomial right angle

Step-by-step explanation:

Set up the Pythagorean Equation for the two triangles

x^2 + h^2 = 4^2  = 16

(x + 6)^2 + h^2 = 8^2 = 64

x^2 +    h^2 = 16                        Subtract. That will get rid of h^2

(x + 6)^2 - x^2 = 64 - 16            Expand the brackets. combine the right.

x^2 + 12x+36 - x^2 = 48           Combine

12x + 36 = 48                            Subtract 36 from both sides

12x +36 -36 = 48-36                 Combine

12x = 12                                      Divide by 12

12x/12 = 12/12

x = 1

x^2 + h^2 = 4^2

1^2 + h^2 = 16

h^2 = 15

h = sqrt(15)  

child does not get an education so she can use the molla on junk

part a

x     y

0     8

1     7.5

2     7

3     6.5

4     6

5     5.5  

for every hour i deducted .5 inches from the length of the candle

part b

it is a function because for every x value there is only one y value

part   c

for every x value there is only one y value

x       y

0       8

1       7.6

2       7.2

3       6.8

step-by-step explanation: