Line jk passes through points j(–3, 11) and k(1, –3). what is the equation of line jk in standard form?

7x + 2y = –1
7x + 2y = 1
14x + 4y = –1
14x + 4y = 1

For this case we must find the slope of the JK line:

Substituting the JK points we have:

So, the equation is:

We find the cut point:

Then, finally the equation is:

Manipulating algebraically:

Option B

ANSWER

EXPLANATION

The given line JK passes through points J(–3, 11) and K(1, –3)

We obtain the slope using the formula;

.The equation is given by

c.   x=2.4cm

step-by-step explanation:

similar triangles are triangles which have the same shape but not the same size. this means their angle measures are equal but their side lengths are not instead they are proportional. to solve, we will set up a proportion and solve.

a proportion is two equal ratios set equal to each other. we form the ratios by finding corresponding sides (sides which match to each other on both triangles by their position). out ratios will be one side of the small triangle over the corresponding side on the big triangle as shown below:

.

to solve the proportion, we'll cross multiply by multiplying numerator with denominator across the equal sign.