Two cars started moving from san jose to san diego. the speed of the faster car was 12 mph less than twice the speed of the other one. in 6 hours the faster car got to san diego, and by that time the slower one still was 168 miles away from the destination. find their speeds.

Speed of the faster car is 68 mph and speed of slower car is 40 mph.

Step-by-step explanation:

Let the faster car has the speed = x mph

and slower car has the speed = y mph

Let the distance between San Jose and San Diago = d miles

Now we will form the first equation.

"Speed of the faster car was 12 mph less than twice the speed of the slower one"

x = 2y -12 ----------(1)

Since "faster car cover the distance d in 6 hours"

so,

"By that time the slower car still was 168 miles away from the destination"

so,

y = x - 28 {since } ---------(2)

By substitution method,

x = 2(x - 28) - 12

x = 2x - 56 - 12

x - 2x = - 68

x = 68 mph

By putting x = 68 in equation 2

y = 68 - 28

y = 40 mph

Therefore, speed of the faster car is 68 mph and speed of slower car is 40 mph

you probably already have the answer but anyways it's b. 15.0

step-by-step explanation:

i think the amount would be $140.62