What is the point-slope form of a line with slope -5 that contains the point
(2,-1)?
o a. y-1 = 5(x+2)
o b. y+1 =-5(x-2)
o c. y+ 1 = 5(x + 2)
o d. y-1 = -5(x-2)

y + 1 - 5(x - 2)

Step-by-step explanation:

Borrow (2, -1):  Substitute 2 for x and -1 for y, and -5 for m in  y = mx + b:

-1 = -5(2) + b.  Then b = 9, and the desired equation in point-slope form is:

y - (-1) = -5(x - 2), or

y + 1 - 5(x - 2)

find the vertical and horizontal asymptotes of the function f x = 5 x − 1 . to find the vertical asymptote, equate the denominator to zero and solve for . since the degree of the polynomial in the numerator is less than that of the denominator, the horizontal asymptote is .

step-by-step explanation: