Find the solution set.
x^2 – 5x = 0

x=0  and x=5

Step-by-step explanation:

x^2 – 5x = 0

Factor out an x

x(x-5) = 0

Using the zero product property

x=0 and x-5 =0

Solving

x=0 x-5+5 = 0+5

x=0  and x=5

substitute,

circle 1 = 5

circle 2 = 20

circle 3 = 44

in this case no matter how you add, you will always get a perfect square..

hence proved

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