What the equation of the quadratic function in standard form represented by the graph

x^2 +6x +8

Step-by-step explanation:

The zeros of the graphed function appear to be (-4, 0) and (-2, 0). It appears the vertex is (-3, -1).

The standard form of the function with zeros p and q is ...

(x -p)(x -q) = x^2 -(p+q)x +pq

So, for zeros p=-4, q=-2, the standard form is ...

x^2 -(-4-2)x +(-4)(-2) = x^2 +6x +8

We can check to make sure the above vertex point satisfies this function:

(-3)^2 +6(-3) +8 = 9 -18 +8 = -1

The vertex satisfies the function we wrote, so there are no additional vertical scale factors required.

The function is ...

y = x^2 +6x +8

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

the required function is .

step-by-step explanation:

from the given table it is noticed that the graph passing through (-3,7), (0,4), (3,1) and (8,-4).

it is a linear function because the value of y is decrease by one as the value of x increase by 1.

the slope of the function is

the slope of the function is -1 and the y-intercept is 4.

the slope intercept form is

where, m is slope and b is y-intercept.

therefore the required function is . the graph of this function is shown below.