Given the function f(x) = 2x + 6/x^2 + 5x + 6 , evaluate the function with the domain values {-3, -2, 0, 2, 3}. what is the valid domain of this function? show all work.

domain; x<0 or x>0

Step-by-step explanation:

We have been given the following function;

f(x) = 2x + 6/x^2 + 5x + 6

We need to evaluate the values of f(x) for the following domain values;

{-3, -2, 0, 2, 3}

f(-3) = 2(-3) + 6/(-3)^2 + 5(-3) + 6

      = -43/3

f(-2) = 2(-2) + 6/(-2)^2 + 5(-2) + 6

      = -6.5

f(0) = 2(0) + 6/(0)^2 + 5(0) + 6

     = undefined

f(2) = 2(2) + 6/(2)^2 + 5(2) + 6

     = 21.5

f(3) = 2(3) + 6/(3)^2 + 5(3) + 6

     = 83/3

The function is real and defined for every value of x in its domain except where x = 0 . This is a point of discontinuity.

Find the attachment below;

7

step-by-step explanation:

find the vertical and horizontal asymptotes of the function f x = 5 x − 1 . to find the vertical asymptote, equate the denominator to zero and solve for . since the degree of the polynomial in the numerator is less than that of the denominator, the horizontal asymptote is .

step-by-step explanation: