Find the perimeter of a field that has length 2/x + 1 and width 5/x^2 -1.

a) 2x + 3/(x + 1)(x - 1)
b) 10/(x + 1)(x - 1)
c) 7/(x + 1)(x - 1)
d)4x + 6/(x + 1)(x - 1)

D)4x + 6/(x + 1)(x - 1)

Step-by-step explanation:

A field is basically a rectangle, so to find the perimeter of our field we are using the formula for the perimeter of a rectangle

where

is the perimeter

is the length

is the width

We know from our problem that the field has length 2/x + 1 and width 5/x^2 -1, so and .

Replacing values:

Notice that the denominator of the second fraction is a difference of squares, so we can factor it using the formula where is the first term and is the second term. We can infer that and . So, . Replacing that:

We can see that the common denominator of our fractions is . Now we can simplify our fraction using the common denominator:

We can conclude that the perimeter of the field is D)4x + 6/(x + 1)(x - 1).

hey seth! : )

i’m not 100% sure, but i think it’s b

hope this ya : p

miss u!

- nicole