Drag each tile to the correct box. arrange the equations in order from least to greatest bed on their solution. equation a: 5( x-6)+3x=3/4(2x-8) equation b: 2.7(5.1x+4.9)=3.2+28.9 equation c: 5(11x-18)=3(2x+7)

B

C

A

Step-by-step explanation:

Find the value of x in each equation then compare the solutions from the least to the greatest

In A

5( x-6)+3x=3/4(2x-8) Open brackets

5x-30+3x=3/2x-6

5x+3x-30=3/2x-6

8x-3/2x=-6+30collect like terms

16x-3x=48

13x=48dived both sides by 13

x=48/13 = 3.7

In B

2.7(5.1x+4.9)=3.2+28.9open bracket

13.77x+13.23=32.1

13.77x=32.1-13.23collect like terms

13.77x=18.87

x=18.87/13.77divide both sides by 13.77

x=1.37

In C

5(11x-18)=3(2x+7)open brackets

55x-90=6x+21

55x-6x=21+90collect like terms

49x=111divide both sides by 49 to get x

x=111/49 = 2.27

From the solutions, the least value of x is in B, then C ,and finally A

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b