Which product of prime polynomials is equivalent to 36x3 – 15x2 – 6x? x(3x – 2)(4x + 1) 3x(3x – 2)(4x + 1) 3(x2 + 1)(4x – 1) 3(x2 + 1)(4x + 1)

3x (3x-2)(4x+1)

Step-by-step explanation:

36x^3 – 15x^2 – 6x

factor out the "3x"

3x (12x^2-5x-2)

3x(3x - 2) (4x + 1)

= 9x^2 - 6x (4x + 1)

= 36x^3 + 9x^2 + -  24x^2 - 6x

= 36x^3 - 15x^2 - 6x

hope this helps!

(x, y)→(x − 8, y − 7)

step-by-step explanation:

enjoy!