Given: circle k(o)

m∠ofq = 52°, m fq = (5x+1)

find: x

x=15°

Step-by-step explanation:

step 1

Find the measure of arc QD

we know that

The inscribed angle is half that of the arc it comprises.

so

m∠OFQ=(1/2)[arc QD]

substitute the given value

52°=(1/2)[arc QD]

104°=[arc QD]

arc QD=104°

step 2

Find the value of x

Remember that the diameter divide the circle into two equal parts

so

arc FQ+arc QD=180°

we have

arc QD=104°

arc FQ=(5x+1)°

substitute

(5x+1)°+104°=180°

5x=180°-105°

x=15°

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

4 + 5 7/9= 9 7/9

step-by-step explanation: