Triangle abc is similar to triangle def . the length of ac is 10 cm. the length of bc is 15 cm. the length of df is 6 cm.
what is the length of ef?

12

6

10

9

  9 cm

Step-by-step explanation:

Side lengths of similar triangles are proportional. BC is 1.5 times the length of AC, so EF will be 1.5 times the length of DF:

  1.5·6 cm = 9 cm

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

answer is 144

step-by-step explanation: