What is the solution to the system of linear equations? 2x+4y=20 and 3x+2y=26

Here is the process of how I did it:

Step 1:     Make this equation : 2x+4y = 20 equal x by isolating x and bring everything else on the right side of the equation

2x + (4y-4y) = 20 - 4y

2x = 20 - 4y

x = 10 - 2y

Step 2: In the other equation given (3x+2y=26) every time you see an x replace it with the equation solved above (x = 10 - 2y). This will help you find the y

3x+2y=26 ---> 3(10 - 2y)+2y=26

10(3) - 2y(3) + 2y = 26

30 - 6y + 2y = 26

(30-30) - 4y = (26 - 30)

y = 1

Step 3: In the equation you found in step 1 (x = 10 - 2y) plug 1 into all the y's so you can find x

x = 10 - 2y ---> x = 10 - 2(1)

x = 10 - 2

x = 8

Hope this helped!

location: point 0

step-by-step explanation:

well, -8 to 10 on a number line is 18 spaces.

1/9 of 18 is 2.

so, 4/9 of 18 must be 8.

8 spaces from -8 (a) is 0.

so, 4/9 of the way from -8 to 10 is 0!

i dont know sorry

step-by-step explanation: