The length of a rectangle is 2 cm more than four times the width. if the perimeter of the rectangle is 84 cm, what are its dimensions

Length 34 cm

Width 8 cm

Step-by-step explanation:

Let

x> the length of the rectangle

y> the width of the rectangle

we know that

The perimeter of rectangle is equal to

P=2(x+y)

P=84 cm

so

84=2(x+y)

42=x+y > equation A

x=4y+2 > equation B

substitute equation B in equation A and solve for y

42=(4y+2)+y

5y=42-2

y=40/5=8 cm

Find the value of x

x=4y+2 > x=4(8)+2=34 cm

The dimensions are

Length 34 cm

Width 8 cm

answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column

true

step-by-step explanation:

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