We want to know the probability that a student selected randomly from her class would have an “a” (90 or above) in her class. find the probability. explain how to find the probability

there are 91 students in the class and 35 students received a 90 or above.

38.46%

Step-by-step explanation:

There are 91 students and 35 of them received a score of 90 or above.

So, there are 35/91 students with an A grade.

The probability to pick a random student that would be the same proportion that those who got the right score, so 35 / 91 = 0.3846 or 38.46%

38.46% of chances to pick someone who got an A (90 score or above), and, the opposite, 61.54% of chances to pick someone who didn't get an A.  That's a strong class!

38.46% of the class received an "A"

Step-by-step explanation:

The Class has a total student count of 91 students. Out of those 91 students 35 of them received an "A" (90 or above). Meaning the percentage of students in the whole class who received a 90 or above is calculated by dividing the amount of students who received an "A" by the total amount of students in the class, as shown below.

0.3846 * 100 = 38.46% ...... we multiply the decimal by 100 to get the percent

So 38.46% of the class received an "A"

I hope this answered your question. If you have any more questions feel free to ask away at .

b

step-by-step explanation:

the equation of the parallel line would be y = 2x + 9

step-by-step explanation:

to start we need to find the slope of the original line. we can do that by looking at the coefficient of x, which is 2

since the slope of the original line is 2 and parallel lines have the same slope, we know the new line will also have 2 slope. now we can use that along with the point given in point-slope form to get the find equation.

y - y1 = m(x - x1)

y - 5 = 2(x + 2)

y - 5 = 2x + 4

y = 2x + 9