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it’s only 1 question and i’m giving as many points possible!

solve the system of equations algebraically. show all of your steps.

y=x^2 + 2x

y=3x + 20

ANSWER

[-4,5]

STEP BY STEP EXPLANATION

ok, so first you plug in the equation 3x+20 into the y in the equation x^2+2x

Your new equation should be 3x+20=x^2+2x

Then you subtract 2x from both sides and your new equation should be x+20=x^2

Then you subtract 20 and x from both sides and your new equation should be 0=x^2-x-20

Then you multiply a with c, which is -20 and then you get b, which is -x or -1. After that you have to find two numbers that is the product of -20 and the sum of -1, which is -5 and 4

Then it would be (x-5)(x+4)=0. You you add 5 to both sides which will be x=5 and then you subtract 4 from both sides, which will be x=-4

Then your final answer is [-4,5]

hope this helped!

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841

i use my brain for prombles like this maybe you could try it

step-by-step explanation: