What are the zeros of the function? f(x) = x^2+2x-35

x = - 7, x = 5

Step-by-step explanation:

To find the zeros equate f(x) to zero, that is

x² + 2x - 35 = 0

To factorise the quadratic

Consider the factors of the constant term (- 35) which sum to give the coefficient of the x- term (+ 2)

The factors are + 7 and - 5, since

7 × - 5 = 35 and 7 - 5 = + 2, hence

(x + 7)(x - 5) = 0

Equate each factor to zero and solve for x

x + 7 = 0 ⇒ x = - 7

x - 5 = 0 ⇒ x = 5

ANSWER

EXPLANATION

The given function is

To find the zeros, we equate the function to zero.

Split the middle term to obtain,

Factor by grouping:

.

c-4 is the final answer! : )

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