The figure below is rotated 270° clockwise about the origin .list the coordinates of the image.

a ( , )

b( , )

c( , )

d( , )

The coordinates of the image are:

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This question is solved applying a 270° clockwise about the origin, which has the following rule:

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Coordinate A:

At the Figure, coordinate A is A(-4,4). Applying the rule:

So the image of A is A'(-4,-4).

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Coordinate B:

At the Figure, coordinate B is B(6,2). Applying the rule:

So the image of B is B'(-2,6).

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Coordinate C:

At the Figure, coordinate C is C(1,1). Applying the rule:

So the image of C is C'(-1,1).

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Coordinate D:

At the Figure, coordinate C is D(-5,3). Applying the rule:

So the image of D is D'(-3,-5).

A similar question is given at link

A (-4, -4), B (-2, 6), C (-1, 1), D(-3, -5)

Step-by-step explanation:

Before the rotation:

A (-4, 4), B (6, 2), C (1, 1), D(-5, 3)

270° rotation clockwise is the same as 90° counterclockwise.  To do that transformation:

(x, y) → (-y, x)

Therefore, the coordinates of the rotated figure are:

A (-4, -4), B (-2, 6), C (-1, 1), D(-3, -5)

sin3a=12/15

step-by-step explanation:

since one side was multiplied by 3 the other side must also be multiplied by 3.