Find the solution set of this system:

y=−3x

x2−4=y

(4,12), (−1,3)

(−1,−3) only

(4,12) only

(−4,12), (1,−3)

(−4, 12), (1, −3)

Step-by-step explanation:

y = −3x

x^2 −4 = y

so

x^2 −4 = −3x

x^2 + 3x - 4 = 0

(x + 4)(x - 1) = 0

x + 4 = 0; x = -4

x - 1 = 0; x = 1

when x = 1, y = -3(1) = -3

when x = -4, y = -3(-4) = 12

Answer

(-4 , 12), (1 , -3)

ANSWER

(−4,12), (1,−3)

EXPLANATION

The system has equations:

y=−3x

We equate the two equations to get:

When x=1,

y=-3(1)=-3

when x=-4, y=-3(-4)=12

The solution is (1,-3) and (-4,12)

4444444444444 i think

the answer is b