Ahmed and gavin are playing both chess and checkers. the probability of ahmed winning the chess games is 45%. the probability of ahmen winning the checkers games is 0.36

which of these events is more likely

a: ahmed wins the chess game

b: ahmed wins the checkers game

c: neither. both events are equally likely

Option A. Ahmed wins the chess game

Step-by-step explanation:

we know that

The probability of Ahmed winning the chess games is 45%

45%=045/100=0.45

The probability of Ahmen winning the checkers games is 0.36

Compare the probability

0.45> 0.36

so

Is more likely that  Ahmed wins the chess game

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below:

translate k to n and reflect across the line containing jk.