The equation of line j is y=2x-8. line k includes the point (-5,-9) and is parallel to line j. what is the equation of like k?
write the equation in slope-intercept form. write the numbers in the equation as proper fractions, improper fractions. or integers

y = 2x + 1.

Step-by-step explanation:

The line j is y = 2x - 8. Comparing this with the standard form of a straight line y = mx + c we see that m (the slope) = 2.

The line k is parallel to j so it has the same slope.

Using the point-slope for of a straight line we can ow find the equation of the line k.

y - y1 = m(x - x1)   where m = slope and (x1, y1) is a point on the line, so

y -  (-9) = 2(x - (-5))

y + 9 = 2(x + 5)

y + 9 = 2x + 10

y = 2x + 1   (answer).

if this is really you s much. i only have 3 points left and i have 2 questions to ask