The dot plots below show the weights of the players of two teams: two dot plots are shown one below the other. the top and the bottom plots have the title team e and team f respectively. below the line for each dot plot is written weight followed by pounds in parentheses. the markings on each line are from 120 till 140 at intervals of 1. for the top plot there are 2 dots each for 130 and 139 and 1 dot each for 126, 127, 132, and 135. for the bottom plot there are two dots each for 120, 121 and 126 and 1 dot each for 123, and 128. based on visual inspection of the dot plots, which team appears to have the larger mean weight? not enough information is available to draw a conclusion. both groups are similar. team f team e

Team E appears to have the larger mean weight.

Step-by-step explanation:

After seeing the dot plot of two teams i.e. Team E and Team F the conclusion that can be drawn regarding the larger mean of the team is that:

Team E is expected to have larger mean since the dots are for the higher values of weights  and hence will result in higher mean. whereas for team F the dots or frequencies are for smaller weights and hence will result in a less mean as compared to team E.

Hence, Team E appears to have the larger mean weight.

109 is the nearest whole number/final answer! : )

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.