100+ points

what is the length of the base of an isosceles triangle if the center of the inscribed circle divides the altitude to the base into the ratio of 12: 5 (from the vertex to the base), and the length of a leg is 60 cm?

Calculate half the base by multiplying the length of a side ( 60 cm) by the fraction of the ratio from the base to the vertex ( 5/12).

Then multiply that by 2 for the width of the base.

60 x 5/12 = 300/12 = 25 cm.

Full width = 25 x 2 = 50 cm.

location: point 0

step-by-step explanation:

well, -8 to 10 on a number line is 18 spaces.

1/9 of 18 is 2.

so, 4/9 of 18 must be 8.

8 spaces from -8 (a) is 0.

so, 4/9 of the way from -8 to 10 is 0!

the answer is b.)

< 1=< 2