Write the equation of the circle with center (−3, 2) and (6, 4) a point on the circle.
a) (x + 3)2 + (y − 2)2 = 13
b) (x + 3)2 + (y − 2)2 = 25
c) (x + 3)2 + (y − 2)2 = 85
d) (x + 3)2 + (y − 2)2 = 117

C

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

here (h, k) = (- 3, 2), thus

(x + 3)² + (y - 2)² = r²

The radius is the distance from the centre of the circle to a point on the circle.

Calculate r using the distance formula

r = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (- 3, 2) and (x₂, y₂ ) = (6, 4)

r =

  = =

Hence

(x + 3)² + (y - 2)² = ( )², that is

(x + 3)² + (y - 2)² = 85 → C

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )

idk

step-by-step explanation: