![\bf \stackrel{radius}{r}=\sqrt{(4-0)^2+(5-0)^2}\implies r=\sqrt{4^2+5^2} \\\\\\ r=\sqrt{16+25}\implies r=\sqrt{41} \\\\[-0.35em] ~\dotfill\\\\ \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{0}{ h},\stackrel{0}{ k})\qquad \qquad radius=\stackrel{\sqrt{41}}{ r} \\\\\\ (x-0)^2+(y-0)^2=(\sqrt{41})^2\implies x^2+y^2=41](/tpl/images/0314/6430/f91f3.png)
What is the general form of the equation for the given circle centered at o(0, 0)?
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Mathematics, 13.10.2019 02:01 tishaadams2160
What is the general form of the equation for the given circle centered at o(0, 0)?
Answers: 1
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