Which of the following is the best estimate of the direction of the given vector?

The direction of the given vector is 45° N of W

Step-by-step explanation:

* Lets revise the four directions with the four quadrants

- The four directions are:

# North which represented by the positive part of y-axis

# South which represented by the negative part of y-axis

# East which represented by the positive part of x-axis

# West which represented by the negative part of y-axis

∴ The first quadrant is between the East and the North

∴ The second quadrant is between the West and the North

∴ The third quadrant is between the West and the South

∴ The fourth quadrant is between the East and the South

* The direction of any vector is tan Ф, where Ф is the angle between

 the vector and the x-axis, then:

- The direction of North of East is 45° ⇒ first quadrant

- The direction of North of West is 45° ⇒ second quadrant

- The direction of South of West is 45° ⇒ third quadrant

- The direction of South of East is 45° ⇒ fourth quadrant

* Now lets solve the problem

∵ The direction of the vector is between the North and the West

  (its vertex in the second quadrant)

∴ Its direction is 45° North of West

* The direction of the given vector is 45° N of W

50*10 is greater

step-by-step explanation:

if you add the zero from 10 to 50, it will give you a bigger number.