Me. i'm so desperate not even my group chat is

5 between Martin's place and the school

Step-by-step explanation:

I don't know if you can draw a diagram from by directions, but you can try. It will help you to see the problem.

Draw

Draw a line that looks like this on your paper.

<:

school         X        Martin's place

Now draw a line going upwards from the arrow head.

∧                 Haley's place.

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<:

school       x      Martin's place

Label the distance from the school to Haley's place as 12

I can't draw a line between martin's place and Haley's but you can. Label it as 13

So the givens are

c = distance between Haley's place and Martin's = 13

b= distance from the school to Haley's is 12

a = ? Distance from Martin't and the school = x

Formula

c^2 = a^2 + b^2

Solution

13^2 = 12^2 + a^2

169 = 144 + a^2          Subtract 144 from both sides.

169 - 144 = 144 - 144 + a^2

25 = a^2

sqrt(25) = sqrt(a^2)

a = 5              

it's 100

step-by-step explanation:

22, 28, 34, 40, 46

b)   f(n) = 6n + 16

  n = what is the number of the row ( 22 would be row 1) so if we replaced n with 1, we would get 22

c)   the  14th  row will have 100 seats

(1)   (2)   (3)   (4)   (5)   (6)   (7)   (8)   (9)   (10) (11) (12) (13) (14)

22 | 28 | 34 | 40 | 46 | 52 | 58 | 64 | 70 | 76 | 82 | 88 | 94 | 100

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