Abag contains six red marbles three blue marbles and five green marble the three marbles are drawn out of the bag what is the probability to the nearest one hundredth that all three marbles will be drawn red?

Step-by-step explanation:

Red = 6

Blue = 3

Green = 5

Total = 14

First marble = 6/14  = 3/7  You now have 5 reds and 13 total

Second Marble = 5 * 13  which brings you down to 4 red and 12 total.

Third Marble = 4/12 = 1/3

Result

P(3 Red) = 3/7 * 5/13 * 1/3     cancel the 3s

P(3 Red) = 1/7 * 5/13

P(3 Red) = 5/91

P(3 Red) = 0.0549 . Rounding to the nearest 1/100 depends on what you have been told about rounding. I would say the answer is 0.05 but your teacher may say something different.