Write a polynomial function in standard form with zeros at 1,2 and 3. !

a. f(x)=(x+1)(x+2)(x+3)
b. f(x)=x^3-6x^2+11x-6
c. f(x)=(x-1)(x-2)(x-3)
d. f(x)=x^3+6^2+11x+6

option B) f(x)=x^3-6x^2+11x-6

Step-by-step explanation:

Zeros means the point at which a given function becomes zero for the value of input.

In given case, zeros of f(x) is required at points 1,2 and 3.

Graphically the point on x-axis where the function line intersects the x-axis is the zero of the function i.e. the function value is 0,

hence

f(x)=0 when x=1

x-1=0

f(x)=(x-1)

f(x)=0 when x=2

x-2=0

f(x)=(x-2)

f(x)=0 when x=3

x-3=0

f(x)=(x-3)

Thus f(x)=(x-1)(x-2)(x-3)

Writing the above polynomial in standard form:

f(x)=x^3-6x^2+11x-6 !

after simplifying it i got: -36.25 as my answer. hope that !