The number of instructions n performed per second by a computer varies directly as the speed s of the computer's internal processor. a processor with a speed of 20 megahertz can perform 1 comma 600 comma 000 instructions per second.

a) find an equation of variation.

b) how many instructions per second will the same processor perform if it is running at a speed of 180 megahertz?

a)

The equation of variation is;

N = 80000*S

b)

14400000

Step-by-step explanation:

We are informed that the number of instructions N performed per second by a computer varies directly as the speed S of the computer's internal processor. This means that N and S are directly proportional;

N∝S

Introducing a constant of proportionality, k;

N=k*S

We shall find the value of k by using the information given;

N = 1600000

S = 20

k = 1600000/20

  = 80000

a)

The equation of variation is thus;

N = 80000*S

b)

We are required to find N when S = 180

Using the equation of variation obtained above;

N = 80000 (180)

   = 14400000

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

-81 -56 -27 0 81

step-by-step explanation: