Mathematics, 30.10.2019 13:31 izayahclark5123

Find the vertex, focus, directrix, and focal width of the parabola.
-1/16x^2 = y

a. vertex: (0, 0); focus: (0, -4); directrix: y = 4; focal width: 16
b. vertex: (0, 0); focus: (-8, 0); directrix: x = 4; focal width: 64
c. vertex: (0, 0); focus: (0, 4); directrix: y = -4; focal width: 4
d. vertex: (0, 0); focus: (0, -4); directrix: y = 4; focal width: 64

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Find the vertex, focus, directrix, and focal width of the parabola.
-1/16x^2 = y

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