What catapulted object hit the ground first?

catapult a:
h(x)= -16x^2+64x+17

catapult b:
time- 0,0.5,1.0,1.5,2.0,2.5,3.0,3.5
height- 28,48,60,64,60,48,28,0

answers:

object from catapult b

they reached the ground at the same time

object from catapult a

it went up but then never came down

Object from Catapult B

Step-by-step explanation:

The question is on time of flight in falling objects

Given catapult A: h(x)= -16x^2+64x+17, find the height the object will reach at time 2.0

substitute value x=2 in h(x)= -16x^2+64x+17;

h(2)= -16 × (2)² +64 ×2 +17

h(2) = -16×4 + 145

h(2)= 81

However with catapult B at t=2.0 the height reached will be 60

Solution

Catapult A object will attain h=81, when t=2.0

Catapult B object will attain h=60, when t=2.0

Thus Object from Catapult B will hit the ground first because it covered a lesser distance compared to the object from catapult A

because linear equations are a lot simpler than quadratics equations, and linear equations formula is a lot easier to memorize. that's why i think they're harder.

step-by-step explanation: