Mathematics, 24.11.2019 00:31 idcatall5
The sum of the first 12 terms of an arithmetic progression is 156. what is the sum of the first and twelfth terms?
Answers: 2
![\bf \qquad \qquad \textit{sum of a finite arithmetic sequence} \\\\ S_n=\cfrac{n}{2}(a_1+a_n)\quad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\[-0.5em] \hrulefill\\ n=12\\ S_{12}=156 \end{cases}\implies 156=\cfrac{12}{2}(a_1+a_{12}) \\\\\\ 156=6(a_1+a_{12})\implies \cfrac{156}{6}=a_1+a_{12}\implies 26=a_1+a_{12}](/tpl/images/0388/3896/7ce8b.png)
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The sum of the first 12 terms of an arithmetic progression is 156. what is the sum of the first and...
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