if the first term of a sequence is 8 and the tenth term is 53 what is the common difference?

step by step

Common difference = 5.

Step-by-step explanation:

General term of an arithmetic sequence is a1 + (n - 1)d where a1 = first term and d = common difference.

So here the first term is  8 + (1-1)d = 8 and the 10th term = 8 + (10-1)d = 53

giving 8 + 9d = 53

9d = 45

d = 5.

squares, rhombus, rectangles

you can first factor out the n to get n(1+5). we know that 1+5 is 6, so we just have 6n.