Which is a solution to (x – 3)(x + 9) = –27?

(x-3)(x+9)=-27

Simplify the left side by multiply each pair of parenthesis:

x^2 + 6x -27 = -27

Add 27 to both sides:

x^2 + 6x = 0

Factor X out of each term:

x(x+6) = 0

Set x equal t o zero"

x= 0

Set x+6 equal to zero and solve for x:

x +6 = 6

x = -6

The solution is X = 0 and -6

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted

hello umm i don't understand your question can you explain it more pls

step-by-step explanation: