Adeep-sea exploring ship is pulling up a diver at the rate of 25 ft./min. the driver is 200 feet below sea level how deep it was the diver 10 minutes ago show your thinking

Ten minutes ago, the diver was  450  feet below sea level.

Step-by-step explanation:

Since the diver is being pulled up, measuring his movement for the past  10 minutes requires that we use  −25  for the movement over those  10  minutes. So, his depth  10 minutes ago is given by the expression

−200−25(10)

−200

−250

−450

So,  10  minutes ago, the diver was  450 feet below sea level.

The diver 450 feet deep into sea 10 minutes ago.

Step-by-step explanation:

At present position ,depth at which diver was = 200 feet

Rate at which diver is pulled up = 25 ft/min

Let the depth of the diver 10 minutes ago be x

The depth of the diver 10 minutes ago will be sum of present position and distance covered by exploring ship by pulling diver in a 10 minutes.

x = 200 + 25ft/min × 10 = 200 ft + 250 ft = 450 ft

The diver 450 feet deep into sea 10 minutes ago.

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47