If the graph f(x)= 9x^2+37x+41/3x+5 has an oblique asymptote at y=3x+k what is the value of k

Step-by-step explanation:

To find out oblique asymptote we divide the polynomials using long division

To find quotient divide the first term. then multiply the answer with 3x+5 and write it down. Subtract it from the top. Repeat the process till we get remainder.

                            ------------------------------

                           -------------------------------------(Subtract)

                                          ------------------------------------(subtract)

Quotient is that is our oblique asympotote

the value of k is 22/3

Step-by-step explanation:

The oblique asymptote of

,

We perform the long division as shown in the attachment.

The quotient is;

Comparing to 3x+k

Hence the value of k is

what is the starting amount? the question is not clear sorry.

step-by-step explanation: