Rectangle a has a length of 2x + 6 and a width of 3x. rectangle b has a length of x + 2 and an area of 12 square units greater than rectangle a's area. what is a simplified expression for the width of rectangle b? x + 2 x + 1 6x + 6 6(x + 2)(x + 1)

So the final answer would be width is 6x + 6

Step-by-step explanation: The formula for Area is Length x width.

So A = (2x + 6)(3x) and the result is: 6x^2 + 18x

Now, let y be the width of rectangle B.

(x+2) (y) = 6x^2 + 18x + 12

(x+2) y = 6(x+1)(x+2)

y = 6(x+1)

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.

step-by-step explanation: